php – 未捕获的异常：jQuery UI选项卡：不匹配的片段标识符

所有.我已经构建了一个简单的jQuery / PHP聊天程序,运行得相当好.但是,我想添加一个功能,如频道或房间.理想情况下,我想在聊天的顶部使用标签来管理用户所在的房间(只有2个).我认为这将是一个简单的任务,我之前已经看到类似的事情,但是当单击选项卡时,我一直收到未捕获的异常错误,并且源无法正确加载.我将发布整个聊天系统的代码,因为我觉得问题可能存在于其中.

jquery

page = {
    getChat: function() {
        $.ajax({
            url: 'game_src.PHP',data: 'mode=getChat',dataType: 'html',cache: false,success: function(res){
                $("#chatBox").html(res);
            }
        });
    }
};

$("#submitmsg").click(function(){
    var clientmsg = $("#usermsg").val();
    $.ajax({
        url : 'game_src.PHP',data: 'mode=chatSubmit&msg=' + encodeURIComponent(clientmsg)
    });
    $("#usermsg").attr("value","");
    return false;
});

setInterval(page.getChat,4000);

$("#chatChannel").tabs({
    cookie: { expires: 1 },});

聊天机构

<?PHP
if($user->data['user_id'] == ANONYMOUS)
{

}
else
{
    ?>
    <div id="chatChannel">
        <ul>
            <li><a href="#global">Global</a></li>
            <li><a href="#alli">Alliance</a></li>
        </ul>
    </div>
    <form name="message" action="">  
        <input name="usermsg" type="text" id="usermsg" size="25" />  
        <input name="submitmsg" type="submit" id="submitmsg" value="Send" />  
    </form>
    <br />
    <?PHP
}
?>
<div id="chatBox" style="border:1px solid black;background-color: rgba(255,255,0.3);height:400px;overflow:auto;">
    <div id="global">
    <?PHP
    $chatMsgs = array();
    $limit = time()-86400;

    $sql = 'SELECT COUNT(chat_id) as count FROM '.CHAT_TABLE.' WHERE chat_channel = 0 AND chat_time > '.$limit;
    $result = $db->sql_query($sql);
    $row = $db->sql_fetchrow($result);
    $count = $row['count'];

    if($count > 0)
    {
        $sql = 'SELECT * FROM '.CHAT_TABLE.' WHERE chat_channel = 0 AND chat_time > '.$limit.' ORDER BY chat_time DESC';
        $result = $db->sql_query($sql);
        while($row = $db->sql_fetchrow($result))
        {
            $chatMsgs[] = array(
                'chat_time' => $row['chat_time'],'chat_msg' => $row['chat_msg'],'chat_user' => $row['chat_user'],'chat_channel' => $row['chat_channel']
            );
        }

        foreach($chatMsgs as $msg)
        {
            $sql = 'SELECT username FROM '.USERS_TABLE.' WHERE user_id = '.$msg['chat_user'];
            $result = $db->sql_query($sql);
            $row = $db->sql_fetchrow($result);
            $username = $row['username'];

            echo '<div class="chatMsg" style="border-bottom:1px solid black;">';
            echo '<div class="chatUsr">'.$username.' says:</div>';
            echo '<div class="chatUsrMsg" style="float:left;">'.$msg['chat_msg'].'</div>';
            echo '<div class="chatMsgTime" style="float:right;">'.date("g:i a",$msg['chat_time']).'</div>';
            echo '</div>';
            echo '<br />';
            echo '<hr />';
        }
    }
    else
    {
        echo '<div class="chatMsg">nothing is heard but the sound of crickets...</div>';
    }
    ?>
    </div>
    <div id="alli">
    <?PHP
    $chatMsgs = array();
    $limit = time()-86400;

    $sql = 'SELECT COUNT(chat_id) as count FROM '.CHAT_TABLE.' WHERE chat_channel = 1 AND chat_time > '.$limit;
    $result = $db->sql_query($sql);
    $row = $db->sql_fetchrow($result);
    $count = $row['count'];

    if($count > 0)
    {
        $sql = 'SELECT * FROM '.CHAT_TABLE.' WHERE chat_channel = 1 AND chat_time > '.$limit.' ORDER BY chat_time DESC';
        $result = $db->sql_query($sql);
        while($row = $db->sql_fetchrow($result))
        {
            $chatMsgs[] = array(
                'chat_time' => $row['chat_time'],$msg['chat_time']).'</div>';
            echo '</div>';
            echo '<br />';
            echo '<hr />';
                    }
    }
    else
    {
        echo '<div class="chatMsg">nothing is heard but the sound of crickets...</div>';
    }
    ?>
    </div>
</div>

我要在getChat jquery函数中添加一个参数来来回切换,但是我拥有的东西,我被卡住了.谁能指出我正确的方向？